|Equal magnitudes have to the same the same ratio; and the same has to equal magnitudes the same ratio.|
|Let A and B be equal magnitudes and C an arbitrary magnitude.
I say that each of the magnitudes A and B has the same ratio to C, and C has the same ratio to each of the magnitudes A and B.
|Take equimultiples D and E of A and B, and take an arbitrary multiple F of C.
Then, since D is the same multiple of A that E is of B, and A equals B, therefore D equals E.
|But F is another, arbitrary, magnitude. If therefore D is in excess of F, then E is also in excess of F; if equal, equal; and, if less, less.|
|And D and E are equimultiples of A and B, while F is another, arbitrary, multiple of C, therefore A is to C as B is to C.||V.Def.5|
I say next that C also has the same ratio to each of the magnitudes A and B.
With the same construction, we can prove similarly that D equals E, and F is some other magnitude. If therefore F is in excess of D, it is also in excess of E; if equal, equal; and, if less, less.
|And F is a multiple of C, while D and E are other, arbitrary, equimultiples of A and B, therefore C is to A as C is to B.||V.Def.5|
|Therefore, equal magnitudes have to the same the same ratio; and the same has to equal magnitudes the same ratio.|
The corollary is misplaced. There is nothing relevant in the proposition. There's no way it could yield the corollary since the proposition requires all the magnitudes to be of the same kind and the corollary doesn't. But the corollary is valid, and it follows easily from definition V.Def.5.
Next proposition: V.8
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