David E. Joyce
Department of Mathematics and Computer Science
Clark University
Worcester, MA 01610
| 11x + y | x + 2y | ||||
| y | x + y | ||||
| 7x + y | 4x | ||||
| 3x + y | x | ||||
| 2x + y | |||||
There's one more piece of information. The vertical line between the top two squares. On the left you have 15x + y, and on the right x + 3y. Therefore, 14x = 2y. Divide by 2 to get 7x = y. You can satisfy that equation by taking x = 1, and y = 7. Now you can put in numbers.
| 18 | 15 | ||||
| 7 | 8 | ||||
| 14 | 4 | ||||
| 10 | 1 | ||||
| 9 | |||||
On to Puzzle 4.
Back to Puzzle 2.
1999. This page may be printed for classroom use.
David E. Joyce
Department of Mathematics and Computer Science
Clark University
Worcester, MA 01610
The address of this file is http://aleph0.clarku.edu/~djoye/puzzles/square1.html